• # question_answer 4 eV is the energy of the incident photon and the work function in $2eV.$ What is the stopping potential A) 2V B) 4V C) 6V D) $2\sqrt{2}V$

[a]       $E={{W}_{0}}+e{{V}_{0}}\Rightarrow 4eV=2eV+e{{V}_{0}}\Rightarrow {{V}_{0}}=2\ volt$