• # question_answer There are ${{n}_{1}}$ photons of frequency ${{\gamma }_{1}}$ in a beam of light. In an equally energetic beam, there are ${{n}_{2}}$ photons of frequency ${{\gamma }_{2}}$. Then the correct relation is A)  $\frac{{{n}_{1}}}{{{n}_{2}}}=1$ B) $\frac{{{n}_{1}}}{{{n}_{2}}}=\frac{{{\gamma }_{1}}}{{{\gamma }_{2}}}$ C) $\frac{{{n}_{1}}}{{{n}_{2}}}=\frac{{{\gamma }_{2}}}{{{\gamma }_{1}}}$ D) $\frac{{{n}_{1}}}{{{n}_{2}}}=\frac{\gamma _{1}^{2}}{\gamma _{2}^{2}}$

[c] $E=nh\nu \Rightarrow \nu \propto \frac{1}{n}\Rightarrow \frac{{{n}_{1}}}{{{n}_{2}}}=\frac{{{\gamma }_{2}}}{{{\gamma }_{1}}}$.