List I | List II |
Oxidising agent | (p) Disproportionation |
\[M{{n}_{3}}{{O}_{4}}\] | (q) Redox reaction |
\[{{C}_{6}}{{H}_{6}}\] | (r) Decreases oxidation number |
\[2C{{u}^{+}}\xrightarrow{{}}C{{u}^{2+}}\]\[+C{{u}^{0}}\] | (s) Fractional oxidation number |
(E) \[{{H}_{2}}{{O}_{2}}+{{O}_{3}}\xrightarrow{{}}\]\[{{H}_{2}}O+2{{O}_{2}}\] | (t) Oxidation number is -1 |
A) A\[\to \]q, B\[\to \]p, C\[\to \]t, D\[\to \]s, E\[\to \]r
B) A\[\to \]t, B\[\to \]s, C\[\to \]r, D\[\to \]q, E\[\to \]P
C) A\[\to \]r, B\[\to \]t, C\[\to \]s, D\[\to \]p, E\[\to \]q
D) A\[\to \]r, B\[\to \]s, C\[\to \]t, D\[\to \]p, E\[\to \]q
Correct Answer: D
Solution :
[d] [a] Oxidising agent, which undergo in reduction process and decreases its oxidation number. |
[b] It is \[MnO,M{{n}_{2}}{{O}_{3}}\] and O.S. \[=\frac{+8}{3}\] |
[c] \[{{C}_{6}}{{H}_{6}}6x+6=0\] \[x=-1\] |
[d] Disproportionate reaction. |
(e) Redox reaction. |
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