A) infinity
B) pole
C) focus
D) 16.67 cm behind the mirror
Correct Answer: D
Solution :
[d]\[u=-50\,cm,\text{ }f=25\,cm\] |
\[\frac{1}{25}=-\frac{1}{50}+\frac{1}{v},\] |
\[\frac{1}{v}=\frac{1}{25}+\frac{1}{50}=\frac{2+1}{50}=\frac{3}{50}\] |
\[c=\frac{50}{3}=16.6\,cm\] |
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