A) \[d+\frac{f(f-d)}{2f-d}\]
B) \[d-\frac{f(f-d)}{d}\]
C) \[d+\frac{f(f-d)}{2(f+d)}\]
D) \[d+\frac{{{f}^{2}}}{2(f-d)}\]
Correct Answer: A
Solution :
[a] \[\frac{1}{v}-\left[ \frac{1}{(f-d)} \right]=\frac{1}{f}\] \[\Rightarrow \] \[v=\frac{f(f-a)}{2f-d}\Rightarrow {{x}_{f}}=d+v=d+\frac{f(f-d)}{2f-d}\]You need to login to perform this action.
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