A) 4 cm
B) 8 cm
C) 12 cm
D) 16 cm
Correct Answer: C
Solution :
[c] Here, magnification \[m=\frac{f}{m+f}=\frac{20}{-30+20}=-2\frac{{{h}_{i}}}{{{h}_{0}}}\] \[\Rightarrow \] \[{{h}_{i}}=-2{{h}_{0}}\] So, the image is real and inverted. Thus, due to upper lens, image will be formed \[{{h}_{i}}=-2(-2cm)=\] above upper principal axis and similarly for lower lens, 4 cm below lower principal axis. So, the separation between the images is \[4+4+(d)\,cm=12\,cm.\]You need to login to perform this action.
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