A) 12 m
B) 20 m
C) 14 m
D) 10 m
Correct Answer: A
Solution :
[a]For refraction by upper surface |
\[\frac{1.6}{{{V}_{1}}}-\frac{1}{-2}=\frac{1.6-1}{1}\Rightarrow \frac{1.6}{{{V}_{1}}}=0.6-0.5=0.1\] |
\[{{V}_{1}}=16\,m\] |
For refraction by lower surface \[\frac{2}{{{V}_{2}}}-\frac{1}{-2}=\frac{2-1}{1}\] |
\[\frac{2}{{{V}_{2}}}=1-0.5=0.5\] |
\[{{V}_{2}}=\frac{2}{0.5}=4\,m\] |
Distance between images \[=(16-4)=12\,m\]. |
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