A man is standing at the edge of a 1 m deep swimming pool, completely filled with a liquid of refractive index \[\sqrt{3/2}\]. The eyes of the man are \[\sqrt{3}m\] above the ground. A coin located at the bottom of the pool appears to be at an angle of depression of \[\text{3}0{}^\circ \] with reference to the eye of man. Then horizontal distance (represented by \[\times \] in the figure) of the coin from the eye of the man is ???.. mm. |
A) 2000
B) 3000
C) 4000
D) 8000
Correct Answer: C
Solution :
[c] |
\[\sin 60{}^\circ =\sqrt{\frac{3}{2}}\,\,\sin r\,\,\,\,\,\Rightarrow \,\,\,\,r=45{}^\circ \] |
\[\therefore \] S = h = 1 m |
\[y=H\tan \,\,60{}^\circ =3\,m\] |
\[\therefore \] \[x=S+y=4\,m=4000\text{ }mm\] |
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