A) \[\frac{4}{3}\]
B) \[\frac{2}{\sqrt{3}}\]
C) \[\frac{8}{5}\]
D) \[\frac{2}{5}\]
Correct Answer: B
Solution :
[b] When no water is there in the swimming pool, the telescope is along the line PO. When water has been filled into the pool, the person is able to see the setting sun, i.e., refracted ray will be along OP while incident ray is along RP, as shown in figure. That is from the object (sun) to the telescope. |
Let \[\mu \] be refractive index of water, then |
\[\frac{\sin \,{{90}^{o}}}{\sin \,{{60}^{o}}}=\frac{\mu }{1}\]\[\Rightarrow \] \[\mu =\frac{1}{\sin \,{{60}^{o}}}=\frac{2}{\sqrt{3}}\] |
You need to login to perform this action.
You will be redirected in
3 sec