A) 1 g
B) 2 g
C) 10 g
D) 20 g
Correct Answer: A
Solution :
[a] For Dibasic acid \[E=\frac{M}{2}=\frac{200}{2}=100\] |
\[N=\frac{W\times 1000}{E\times V(\text{in }ml)}\] |
\[\frac{1}{10}=\frac{W\times 1000}{100\times 100}=W=1gm\]. |
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