A) 28 g
B) 20 g
C) 40 g
D) 23 g
Correct Answer: C
Solution :
[c] We know that, one mole of an element \[=6.02\times {{10}^{23}}\] atoms |
= Atomic weight of the element |
Now, \[1.58\times {{10}^{22}}\] atoms weigh 1.05 g |
\[\therefore \] \[6.02\times {{10}^{23}}\] atoms weigh |
\[=\frac{(1.05\times 6.02\times {{10}^{23}})}{1.58\times {{10}^{22}}}\] |
= 40 g |
Atomic weight of \[X=40g\] |
You need to login to perform this action.
You will be redirected in
3 sec