A) 16.0 and 56.0
B) 8.0 and 28.0
C) 56.0 and 16.0
D) 28.0 and 8.0
Correct Answer: A
Solution :
[a]\[\frac{32}{2x+3y}=0.2;\,\,\frac{92.8}{3x+4y}=0.4\] Hence: \[x=56\And y=16\].You need to login to perform this action.
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