A) 272 mL
B) 68 mL
C) 136 mL
D) 204 mL
Correct Answer: C
Solution :
[c] Molarity of given sulphuric acid |
\[=\frac{98}{98}\times \frac{1.84}{100}\times 1000=18.4\,mol\,d{{m}^{-3}}\] |
\[{{M}_{1}}{{V}_{1}}={{M}_{2}}{{V}_{2}}\] |
\[{{V}_{1}}=\frac{0.5\times 5}{18.4}=0.136\,d{{m}^{3}}=136\,mL\] |
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