A) 10%
B) 20%
C) 22%
D) 11%
Correct Answer: D
Solution :
[d] Idea This problem is based on mole concept. This problem can be solved by considering value of mole % of Mg as. |
Let mole % of \[^{26}Mg=x\] |
\[\frac{(21-x)25+x(26)+79(24)}{100}=24.32\] |
\[x=10%\] |
So, %\[^{25}Mg=21-10=11\]% |
TEST Edge Mole % of isotope present in any compound are also be asked by supplying required parameters in questions. So, students are \[h{{v}_{1}}=h{{v}_{0}}+\frac{1}{2}mu_{1}^{2}\] advised to keep a good understanding of mole concept. |
You need to login to perform this action.
You will be redirected in
3 sec