A) \[464\text{ }kJ\text{ }mo{{l}^{-1}}\]
B) \[-464\text{ }kJ\text{ }mo{{l}^{-1}}\]
C) \[232\text{ }kJ\text{ }mo{{l}^{-1}}\]
D) \[-232\text{ }kJ\text{ }mo{{l}^{-1}}\]
Correct Answer: A
Solution :
[a] \[{{H}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)\to {{H}_{2}}O(g)?h=-249\] |
Let the bond enthalpy of \[O-H\] is x. Then \[\Delta H=\sum B.E.\] of reactant \[-\sum B.E.\] of product |
\[-249=433+\frac{1}{2}\times 492-2x\] |
\[\Rightarrow \] \[x=46\,kJ\,mo{{l}^{-1}}\] |
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