• # question_answer A carnot engine has the same efficiency between  800 K to 500 K and x K to 600 K. The value of x is A) 1000 K B) 960 K C) 846 K D) 754 K

 [b] In first case, $({{\eta }_{1}})=1-\frac{500}{800}=\frac{3}{8}$ and in second case, $({{\eta }_{2}})=1-\frac{600}{x}$ Since ${{\eta }_{1}}={{\eta }_{2}},$ therefore $\frac{3}{8}=1-\frac{600}{x}$ or $\frac{600}{x}=1-\frac{3}{8}=\frac{5}{8}$or$x=\frac{600\times 8}{5}=960K$