A) 750 joules
B) 1728 joules
C) 1500 joules
D) 3456 joules
Correct Answer: B
Solution :
[b] \[{{W}_{iso}}=\mu RT{{\log }_{e}}\frac{{{V}_{2}}}{{{V}_{1}}}=1\times 8.31\times 300{{\log }_{e}}\frac{20}{10}=1728J\]You need to login to perform this action.
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