• # question_answer In thermodynamic process, 200 Joules of heat is given to a gas and 100 Joules of work is also done on it. The change in internal energy of the gas is A) 100 J B) 300 J C) 419 J D) 24 J

 [b] $\Delta Q=\Delta U+\Delta W$; $\Delta Q=200J$ and $\Delta W=-100J$ Þ $\Delta U=\Delta Q-\Delta W=200-(-100)=300J$