A) 372K, 310K
B) 772K, 312K
C) 672K, 610K
D) None of these
Correct Answer: A
Solution :
[a] \[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}\] where \[{{T}_{1}}\And {{T}_{2}}\] are source & sink temperatures respectively. |
\[\frac{1}{6}=1-\frac{{{T}_{2}}}{{{T}_{1}}}\] (1) |
Modified case, |
\[\frac{1}{3}=1-\frac{{{T}_{2}}-62}{{{T}_{1}}}\] ..(2) |
Solving (1) and (2), we get |
\[{{T}_{1}}=372K,\,{{T}_{2}}=310\,K\] |
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