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JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Topic Test - Thermodynamics and Thermochemistry (8-5-21)

  • question_answer
    For a carnot engine, the source is at \[500K\] and the sink at \[300K\]. What is efficiency of this engine

    A) 0.2

    B) 0.4

    C) 0.6

    D) 0.3

    Correct Answer: B

    Solution :

    [b] Given that \[{{T}_{1}}=500K,\,\,{{T}_{2}}=300K\]
    By using \[\eta =\frac{{{T}_{1}}-{{T}_{2}}}{{{T}_{1}}}\]\[=\frac{500-300}{500}=\frac{200}{500}=0.4\].


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