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JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Topic Test - Thermodynamics and Thermochemistry (8-5-21)

  • question_answer
    The volume of a gas decreases from \[500\,cc\] to \[300\,cc\] when a sample of gas is compressed by an average pressure of 0.6 atm. During this process 10 J of heat is liberated. The change in internal energy is

    A)  - 2.16 J

    B) 12.156 J

    C) 2.16 J

    D) 101.3 J

    Correct Answer: C

    Solution :

    [c] Here: Change in
                Volume \[(V)=500-300=200cc=0.2\,litre,\]
                Pressure \[(P)=0.6\,atm\]and heat liberated (q) = 10J
                Work done \[(W)=P\Delta V=(0.2\times 0.6)=0.12\,litre-atm\]
                But \[1\,litre-atm=101.3\,J\]. 
                hence \[W=0.12\times 101.3=12.156\,J\]. We also know that heat is liberated, therefore it would be negative. Thus change in \[\Delta E=q+W=-10+12.16=2.16\,J\].


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