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JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Topic Test - Thermodynamics and Thermochemistry (8-5-21)

  • question_answer
    Heat of neutralisation for the given reaction \[NaOH+HCl\to NaCl+{{H}_{2}}O\] is \[57.1\,kJ\,mo{{l}^{-1}}\]. What will be the heat released when \[0.25\,mole\] of \[NaOH\] is titrated against \[0.25\,mole\] of \[HCl\]

    A) \[22.5\,kJ\,mo{{l}^{-1}}\]

    B) \[57.1\,kJ\,mo{{l}^{-1}}\]

    C) \[14.3\,kJ\,mo{{l}^{-1}}\]

    D) \[28.6\,kJ\,mo{{l}^{-1}}\]

    Correct Answer: C

    Solution :

    [c] \[57.1\,\,\times 0.25=14.3\] \[kJ\,mo{{l}^{-1}}\].


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