A) \[7.1{}^\circ C\]
B) \[9.2{}^\circ C\]
C) \[10.5{}^\circ C\]
D) \[12.1{}^\circ C\]
Correct Answer: A
Solution :
\[W=JQ\] \[\Rightarrow \] \[\frac{1}{2}\left( \frac{1}{2}M{{v}^{2}} \right)=J(m.c.\Delta \theta )\] \[\Rightarrow \] \[\frac{1}{4}\times 1\times {{(50)}^{2}}=4.2[200\times 0.105\times \Delta \theta ]\] \[\Rightarrow \] \[\Delta \theta =7.1{}^\circ C\]You need to login to perform this action.
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