A) \[0.3\,Cal\text{/}gm\times {}^\circ C\]
B) \[0.6\,Cal\text{/}gm\times {}^\circ C\]
C) \[0.6\,Cal\text{/}gm\times {}^\circ C\]
D) \[0.8\,Cal\text{/}gm\times {}^\circ C\]
Correct Answer: C
Solution :
\[{{S}_{l}}=\frac{1}{{{m}_{l}}}\left[ \frac{{{t}_{l}}}{{{t}_{W}}}({{m}_{W}}{{C}_{W}}+W)-W \right]\] \[=\frac{1}{300}\left[ \frac{95}{3\times 60}(350\times 1+10)-10 \right]\] \[=0.6\,Cal\text{/}gm\times {}^\circ C\]You need to login to perform this action.
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