A) 250 K
B) 500 K
C) 1000 K
D) 62.5 K
Correct Answer: B
Solution :
\[Q\propto {{T}^{4}}\]\[\Rightarrow \] \[\frac{{{Q}_{1}}}{{{Q}_{2}}}=\frac{T_{1}^{4}}{T_{2}^{4}}\] \[\Rightarrow \] \[T_{2}^{4}=\left( \frac{{{E}_{2}}}{{{E}_{1}}} \right)T_{1}^{4}\] \[\Rightarrow \] \[T_{2}^{4}=\frac{1}{16}\times {{(1000)}^{4}}={{\left( \frac{1000}{2} \right)}^{4}}\]\[\Rightarrow \] \[{{T}_{2}}=500K\]
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