A) 4\[{{\lambda }_{0}}\]
B) 2\[{{\lambda }_{0}}\]
C) \[{{\lambda }_{0}}\]/2
D) \[{{\lambda }_{0}}\]/4
Correct Answer: C
Solution :
\[\because \ {{\lambda }_{m}}T={{{\lambda }'}_{m}}{T}'\] \[\Rightarrow \] \[{{\lambda }_{0}}T={\lambda }'\times 2T\] \[\Rightarrow \] \[{\lambda }'=\frac{{{\lambda }_{0}}}{2}\]You need to login to perform this action.
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