A) 230 W
B) 160 W
C) 9000 W
D) 4150 W
Correct Answer: B
Solution :
[b] The rate at which the filament of the bulb is radiating the energy is equal to the rate at which it is consuming the electrical energy (no energy loss has been considered). So power of bulb is \[P=\sigma eA{{T}^{4}}\]\[=5.67\times {{10}^{-8}}\times 0.7\times 0.5\times {{10}^{-5}}\times {{(3000)}^{4}}\approx 160W\]You need to login to perform this action.
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