A) 8.2 m
B) 9.0 m
C) 11.6 m
D) 12.7 m
Correct Answer: A
Solution :
[a] Horizontal component of velocity |
\[{{v}_{x}}=25\cos 60{}^\circ =12.5\,m/s\] |
Vertical component of velocity |
\[{{v}_{y}}=25\sin 60{}^\circ =12.5\sqrt{3}\,m/s\] |
Time to cover 50 m distance \[t=\frac{50}{12.5}=4\,\sec \] |
The vertical height y is given by |
\[y={{v}_{y}}t-\frac{1}{2}g{{t}^{2}}=12.5\sqrt{3}\times 4-\frac{1}{2}\times 9.8\times 16=8.2\,m\] |
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