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JEE Main & Advanced Physics Two Dimensional Motion Question Bank Topic Test - Two Dimensional Motion

  • question_answer
    The range of a particle when launched at an angle of \[{{15}^{o}}\] with the horizontal is 1.5 km. What is the range of the projectile when launched at an angle of \[{{45}^{o}}\] to the horizontal                 

    A) 1.5 km

    B) 3.0 km

    C) 6.0 km

    D) 0.75 km

    Correct Answer: B

    Solution :

    [b] \[{{R}_{15{}^\circ }}=\frac{{{u}^{2}}\sin (2\times 15{}^\circ )}{g}\]\[=\frac{{{u}^{2}}}{2g}=1.5\,km\]    \[{{R}_{45{}^\circ }}=\frac{{{u}^{2}}\sin (2\times 45{}^\circ )}{g}=\frac{{{u}^{2}}}{g}=1.5\times 2=3\,km\]


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