A particle of mass m collides inelastically with another particle of mass 3m which is at rest. After the collision first particle comes to rest. Then choose the wrong answer |
A) coefficient of restitution between the particles is \[1/3\]
B) loss of kinetic energy during collision is \[\left( 1/3 \right)m{{v}^{2}}\]
C) velocity of second particle after collision is\[v/3\].
D) all of these
Correct Answer: D
Solution :
[d] From conservation of linear momentum velocity of second particle after collision would be \[\frac{V}{3}\] Coefficient of restitution is |
\[e=\frac{relative\,\,velocity\,\,ofseparation}{relative\,\,velocity\,\,of\,approach}=\frac{V/3}{V}=\frac{1}{3}\]Loss in kinetic energy |
\[=\frac{1}{2}v{{V}^{2}}-\frac{1}{2}(3m){{\left( \frac{V}{3} \right)}^{2}}=\frac{1}{3}m{{V}^{2}}\] |
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