Two masses connected by a mass less spring .are placed on a horizontal smooth surface. The spring is initially compressed by 3 cm. The system is released from rest. The velocity (in m/s) of the 2 kg mass, when spring attains natural length is to |
A) \[\sqrt{\frac{3}{2}}\]
B) \[\sqrt{\frac{2}{3}}\]
C) \[\frac{3}{2}\]
D) \[\sqrt{3}B=\left( 1/5\text{ }x\text{ }30 \right)\]
Correct Answer: A
Solution :
[a] \[{{m}_{1}}{{v}_{1}}={{m}_{2}}{{v}_{2}}\]and\[\frac{1}{2}Kx_{0}^{2}=\frac{1}{2}{{m}_{1}}v_{1}^{2}+\frac{1}{2}{{m}_{2}}v_{2}^{2}.\] Solving\[:{{v}_{2}}=\sqrt{\frac{3}{2}}\]You need to login to perform this action.
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