A) \[3\times {{10}^{8}}\] m/s
B) \[1.5\times {{10}^{8}}\] m/s
C) \[6\times {{10}^{8}}\] m/s
D) \[\sqrt{3}\times {{10}^{8}}\]m/s
Correct Answer: B
Solution :
\[\mu =\frac{1}{\sin C}=\frac{1}{\sin 30}=2\] \[\therefore v=\frac{3\times {{10}^{8}}}{2}=1.5\times {{10}^{8}}m/s\]
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