A) 64 m, 44 km/h
B) 64 m, 54 km/h
C) 84 m, 54 km/h
D) 84 m, 60 km/h
Correct Answer: C
Solution :
[c] Let the length of the train be x m. \[\frac{(96+x)}{12}=\frac{(141+x)}{15}\] \[\Rightarrow \] \[15\times (96+x)\,=12\times (141+x)\] \[\Rightarrow \] \[3x=(1692-144)=252\] \[\Rightarrow \] \[x=84\,m\] Speed of the train\[=\frac{(96+84)}{12}m/s\] \[=15\,m/s\] \[=\left( 15\times \frac{18}{5} \right)\,\,km/h=54\,km/h\] |
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