A) 36 km/h, 18 km/h
B) 40 km/h, 20 km/h
C) 44 km/h, 22 km/h
D) 52 km/h, 26 km/h
Correct Answer: D
Solution :
[d] Let the speeds of trains are x and y km/h (where x > y) By condition given in question, \[\frac{100+95}{27}\times \frac{18}{5}=x-y\] (i) and \[\frac{100+95}{27}\times \frac{18}{5}=x-y\] (ii) From Eqs. (i) and (ii), we get \[x-y=26\] and \[x-y=78\] |
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