A) A circle
B) Perpendicular bisector of the line segment AB
C) A line parallel to x-axis
D) None of these
Correct Answer: B
Solution :
Let point be (h, k) then, \[{{(h-a)}^{2}}+{{k}^{2}}={{(h+a)}^{2}}+{{k}^{2}}\] \[\Rightarrow \,\,4ha=0\,\,\Rightarrow \,\,h=0.\] Hence x = 0.
You need to login to perform this action.
You will be redirected in
3 sec
