A) \[{{x}^{2}}+{{y}^{2}}=4\]
B) \[{{x}^{2}}+{{y}^{2}}=16\]
C) \[{{x}^{2}}+{{y}^{2}}=2\]
D) None of these
Correct Answer: B
Solution :
Required locus is \[\sqrt{{{(x-0)}^{2}}+{{(y-0)}^{2}}}=4\] \[\Rightarrow \,\,{{x}^{2}}+{{y}^{2}}=16\].
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