A) A straight line
B) A circle
C) A parabola
D) An ellipse
Correct Answer: B
Solution :
On eliminating q, we get the required locus. Since \[x=a\,(1-\cos \theta )\Rightarrow \,\,x-a=-a\cos \theta \] .....(i) and \[y=a\sin \theta \] .....(ii) Now adding the squares of (i) and (ii), we get \[{{x}^{2}}+{{y}^{2}}-2ax=0\], which is equation of a circle.
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