A) \[{{x}^{2}}+{{y}^{2}}-2=0\]
B) \[{{x}^{2}}+{{y}^{2}}+2=0\]
C) \[{{x}^{2}}+{{y}^{2}}+4=0\]
D) \[{{x}^{2}}+{{y}^{2}}-4=0\]
Correct Answer: D
Solution :
\[{{(x-2)}^{2}}+{{y}^{2}}+{{(x+2)}^{2}}+{{y}^{2}}=16\,\,\Rightarrow \,\,{{x}^{2}}+{{y}^{2}}=4\].You need to login to perform this action.
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