A) Isosceles
B) Scalene
C) Equilateral
D) Right angled
Correct Answer: C
Solution :
(c): Let one angle of the triangle be \[{{a}^{{}^\circ }}\] \[\therefore \] Sum of remaining two angles \[={{180}^{{}^\circ }}-a\] According to me question, \[a=\frac{{{180}^{{}^\circ }}-a}{2}\] \[\Rightarrow \]\[2a+a={{180}^{{}^\circ }}\] \[\Rightarrow \]\[3=~{{180}^{{}^\circ }}\] \[\Rightarrow \] \[a={{60}^{{}^\circ }}\] \[\therefore \]other each angle \[={{60}^{{}^\circ }}\]
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