9th Class Mathematics Triangles Question Bank Triangle

  • question_answer
    in \[\Delta ABC,\text{ }AD\bot BC\] and \[A{{D}^{2}}=BD.DC\] the measure of \[\angle BAC\] is.

    A)  \[{{60}^{{}^\circ }}\]                        

    B)  \[{{75}^{{}^\circ }}\]

    C)  \[{{90}^{{}^\circ }}\]

    D)  \[{{45}^{{}^\circ }}\]

    Correct Answer: C

    Solution :

    (c): In right angled \[\Delta ABD\] and \[\Delta ADC\], \[A{{B}^{2}}=A{{D}^{2}}+B{{D}^{2}}\] And, \[A{{C}^{2}}=A{{D}^{2}}+D{{C}^{2}}\] On adding, \[A{{B}^{2}}+A{{C}^{2}}=2A{{D}^{2}}+B{{D}^{2}}+C{{D}^{2}}\] \[\Rightarrow \]\[A{{B}^{2}}+A{{C}^{2}}=2BD\times CD+B{{D}^{2}}+C{{D}^{2}}\] \[\left[ \therefore A{{D}^{2}}=BD\times CD \right]\] \[\Rightarrow \]\[A{{B}^{2}}+A{{C}^{2}}={{\left( BD+CD \right)}^{2}}\] \[=B{{C}^{2}}\] \[\therefore \] \[\angle BAC={{90}^{{}^\circ }}\]                       


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