A) \[8\sqrt{3}\]
B) \[4\sqrt{3}\]
C) \[4.5\sqrt{3}\]
D) \[3.5\sqrt{3}\]
Correct Answer: D
Solution :
(d) Area of ABC will be \[\frac{\sqrt{3}}{4}{{\left( 4 \right)}^{2}}=4\sqrt{3}\] ADE is right triangle where AD =1, so we will bet \[DE=\sqrt{3}\]and \[AE=2\] So area of \[\Delta ADE\] will be \[\frac{1}{2}\times 1\times \sqrt{3}=\frac{\sqrt{3}}{2}\] So area of BCDE = \[4\sqrt{3}-\sqrt{3}/2=3.5\sqrt{3}\]
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