question_answer

In the figure given below, ABC is an isosceles triangle such that \[\mathbf{AB}=\mathbf{AC}\] and\[\angle \mathbf{B}=\mathbf{3}{{\mathbf{0}}^{{}^\circ }}\], AD is the median to the base BC. Then \[\Delta \mathbf{BAD}\] is:

A)  \[{{80}^{{}^\circ }}\]                       

B)  \[{{40}^{{}^\circ }}\]

C)  \[{{110}^{{}^\circ }}\]                                  

D)  \[{{60}^{{}^\circ }}\]