A) \[\sqrt{15}\,a\] unit
B) \[\frac{\sqrt{15}}{2}\,a\]unit
C) \[\sqrt{17}\,a\]unit
D) \[\frac{\sqrt{17}}{2}\,a\] unit
Correct Answer: B
Solution :
[b] \[A{{D}^{2}}=A{{B}^{2}}-B{{D}^{2}}=4{{a}^{2}}-\frac{{{a}^{2}}}{4}\] \[AD=\sqrt{\frac{15{{a}^{2}}}{4}}=\frac{a}{2}\sqrt{15}\,\text{units}\] |
You need to login to perform this action.
You will be redirected in
3 sec