A) \[240{}^\circ \]
B) \[300{}^\circ \]
C) \[320{}^\circ \]
D) \[360{}^\circ \]
Correct Answer: D
Solution :
[d] Clearly, \[\angle 1+\angle BAE=180{}^\circ \] \[\angle 2+\angle CBF=180{}^\circ \] \[\angle 3+\angle ACD=180{}^\circ \,(\angle 1+\angle 2+\angle 3)\] \[+\,(\angle BAC+\angle CBF+\angle ACD)=540{}^\circ \] \[\Rightarrow \]\[180{}^\circ +(\angle BAE+\angle CBF+\angle ACD)\] \[=540{}^\circ \] \[\Rightarrow \] \[\angle ACD+\angle BAE+\angle CBF=360{}^\circ \] |
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