A) \[90{}^\circ \]
B) \[110{}^\circ \]
C) \[60{}^\circ \]
D) \[-120{}^\circ \]
Correct Answer: A
Solution :
[a] According to the question, \[\because \] OB = OC = Radius of circle \[\therefore \] \[\angle OBC=\angle OCB\] \[\because \] O is the circumcentre of a\[\Delta ABC\] \[\therefore \] \[\angle BOC=2\times \angle BAC\] In\[\Delta BOC,\]\[2\times \angle OBC+\angle BOC=180{}^\circ \] \[(\therefore \angle OBC\angle OCB)\] \[\Rightarrow \] \[2\times \angle OBC+2\times \angle BAC=180{}^\circ \] \[\therefore \] \[\angle OBC+\angle BAC=90{}^\circ \] |
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