A) \[75{}^\circ \]
B) \[60{}^\circ \]
C) \[45{}^\circ \]
D) \[80{}^\circ \]
Correct Answer: B
Solution :
[b] From figure, \[\angle BIC=2\times \angle BAC=120{}^\circ \] And \[IB=IC\] \[\therefore \] \[\angle IBD=\angle ICD\] \[=\frac{180{}^\circ -120{}^\circ }{2}=30{}^\circ \] Now, \[\angle BID=90{}^\circ -30{}^\circ =60{}^\circ \] |
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