question_answer

ABC is an isosceles triangle such that AB = AC and AD is the median to the base BC with \[\angle \,\,ABC=35{}^\circ .\]Then, \[\angle \,BAD\] is [SSC CGL Tier II, 2014]

A) \[35{}^\circ \]

B) \[55{}^\circ \]

C) \[70{}^\circ ~\]

D) \[110{}^\circ \]

Correct Answer: B

Solution :

[b] In\[\Delta \,ABC,\]     \[\angle \,ABD=\angle \,ACD\] = Equal angles of isosceles triangle \[\angle \,A=180-\angle B+\angle C=180-35-35=110{}^\circ \] since, AD is the median \[\therefore \]      \[\angle \,BAD=\frac{\angle A}{2}=\frac{110}{2}=55{}^\circ \]