SSC Quantitative Aptitude Geometry Question Bank Triangles and Their Properties (II)

  • question_answer
    In ABC, P and Q are the middle points of the sides AB and AC respectively. R is a point on the segment PQ such that PR : RQ = 1 : 2. If PR = 2 cm, then BC is equal to

    A) 4 cm

    B) 2 cm

    C) 12 cm

    D) 6 cm

    Correct Answer: C

    Solution :

    [c] Since, P, S Q are the mid-points of AB and BC, therefore \[\frac{AP}{AB}=\frac{PQ}{BC}=\frac{1}{2}\]                          …(i) Now,     \[\frac{PR}{RQ}=\frac{1}{2}\]\[\Rightarrow \]\[\frac{2}{RQ}=\frac{1}{2}\]\[\Rightarrow \]\[RQ=4\] \[\therefore \]      \[PQ=2+4=6\,cm\] Therefore, from Eq. (i), we get \[\frac{6}{BC}=\frac{1}{2}\]\[\Rightarrow \]\[BC=12\,cm\]


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