A) \[AB>AC\]
B) \[AD=AB\]
C) \[AB=AC\]
D) \[AD=AC\]
Correct Answer: C
Solution :
Given, \[AD\bot BC\Rightarrow BD=DC\] In \[\Delta \Alpha \Beta D\]and \[\Delta \Alpha CD\] \[BD=DC\](given) \[AD=AD\](Common side) \[\angle ADB=\angle ADC={{90}^{o}}\] \[\Delta ABD\cong \Delta ADC\][S.A.S congruence] \[\Rightarrow \]\[AB=AC\]You need to login to perform this action.
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