question_answer

In\[\Delta ABC\], \[AD\bot BC\]and\[\angle B=\angle C\]. By which property is\[\Delta ADB\cong \Delta ADC\]?

A)  S.A.S. property  

B)         S.S.S. property

C)         R.H.S. property  

D)         A.S.A. property

Correct Answer: D

Solution :

In\[\Delta ABD\]and \[\Delta ADC,\angle B=\angle C\](Given) \[\Rightarrow \]\[AB=BC\] \[\angle ADB=\angle ADC\]and\[BD=DC\] (Since, \[AD\bot BC.\]) \[\therefore \]\[\Delta ADB\cong \Delta ADC\](By A.S.A property)